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(C)=2C^2-200C+19.000
We move all terms to the left:
(C)-(2C^2-200C+19.000)=0
We get rid of parentheses
-2C^2+C+200C-19.000=0
We add all the numbers together, and all the variables
-2C^2+201C-19=0
a = -2; b = 201; c = -19;
Δ = b2-4ac
Δ = 2012-4·(-2)·(-19)
Δ = 40249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$C_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(201)-\sqrt{40249}}{2*-2}=\frac{-201-\sqrt{40249}}{-4} $$C_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(201)+\sqrt{40249}}{2*-2}=\frac{-201+\sqrt{40249}}{-4} $
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